| Looking a little deeper: Those who looked closely at previous interstellar shuttle pages will notice that it took the same amount of velocity and energy, given ships of equal mass of course, to deflect ships on the 4 ly by 2 ly triangle and the 10 ly by 5 ly triangle. It's the angle of deflection and the initial velocity that matters, not the distance. If you're a bit of a math geek this page will interest you. |
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| There may be other ways to look at this mathematically. I know there's more than one way to show how these equations are derived. This web site is done for fun and the typical web surfer probably doesn't want to be bored with a lot of math. You can email me if you want. Or go here for a more detailed explanation. I am not a mathematical genius so try not to razzle dazzle me! The easiest way of finding the energies when relativity is taken into account would be to program a calculator or a computer. I just made a list of B squared = v/c squared for some deflection velocities and programmed my old TI-82. Yes, I could have gone a lot farther with this but I am kind of lazy and disorganized and I am not doing this for a college class and this website is not the JBIS! Have fun. |
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